Question

if a body is projected with a velocity of 9.8m/s making an angle of 45° with the horizontal ,the range of projectile is​

Answer 1

Answer:

Given, v=9.8 m/s

Range, R=gv2sin2θ=9.8(9.8)2sin(2×450)=9.8 m

So the answer is 9.8m....