If a body is released from a point at a height equal to n times the radius of earth r its velocity on reaching the surface of the earth is
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Answer:V = (2gRn/n+1)^1/2
Explanation: According to conservation of mechanical energy the total energy at point located at a distance of nR from the surface of earth (as mentioned in question) is equal to total energy at the surface of earth.
Equating the two you get the answer ... Answer attached below
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