If a body is thrown up with an initial velocity u and covers a maximum height of h then h is equal to
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Answered by
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heyyaa mate its very simple...
we have formula for max. height ...
h= u^2/2g
hope it helps !!
we have formula for max. height ...
h= u^2/2g
hope it helps !!
Answered by
0
h = (u square/10)+(10* u square)/200
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