if a body is thrown up with the velocity of 15 M per second then find the maximum height attained by the body
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Max height(h) =u^2/2g
where u is velocity
u=15m/sec
g=10m/sec
h = (15)^2/2 *10
225/20
h= 45/4
h=11.25metres is the answer
where u is velocity
u=15m/sec
g=10m/sec
h = (15)^2/2 *10
225/20
h= 45/4
h=11.25metres is the answer
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