if a body is thrown with a speed of 19.6 M per second making an angle of 30° with the horizontal then time of flight is
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Time taken by an object to cover a parabolic path is given by this simple formula
T=2usinx/g
Where T is time period
u is initial velocity
x is the angle made by horizontal
g is gravity
SUBSTITUTING ALL THE VALUES WE GET:
2*19.6*sin 30/9.8
=2*19.6*1/(2*9.8)
=2 seconds
Hence the total time taken is 2 seconds.
__________
HOPE IT HELPS
T=2usinx/g
Where T is time period
u is initial velocity
x is the angle made by horizontal
g is gravity
SUBSTITUTING ALL THE VALUES WE GET:
2*19.6*sin 30/9.8
=2*19.6*1/(2*9.8)
=2 seconds
Hence the total time taken is 2 seconds.
__________
HOPE IT HELPS
Answered by
3
Answer:
Explanation:
Time taken by an object to cover a parabolic path is given by
T=2usinx/g
Where
- T is time period
- u is initial velocity
- x is the angle made by horizontal
- g is gravity
By substituting the given values
(2*19.6*sin 30)/9.8
=(2*19.6*1)/(2*9.8)
=2 seconds
Hence the total time taken is 2 seconds
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