Question

If a body is thrown with speed of 19.6m/s making an angle of a 30° with the horizontal, then the time of flight is

Answer 1

it's a case of projection motion.

in this type of motion, the total time of flight is T

$\frac{2u \sin( \alpha ) }{g}$

where u is the initial velocity and alpha is the angle of projection.

so, T

$\frac{2 \times 19.6 \times \sin(60) }{9.8}$

$= 3.46sec$