If a body loses half of it's velocity on penetrating 3 cm in a wooden block, then how much will it penetrate more before coming to rest.?
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Explanation:
Let initial velocity be v.
Initial Energy =
2
1
mv
2
Final energy =
2
1
m(
2
v
)
2
=
4
1
(
2
1
mv
2
)
Energy lost =
2
1
mv
2
−
4
1
(
2
1
mv
2
)=
4
3
(
2
1
mv
2
),−−−−−−(for 3 cm)
So, Remaining energy =
4
1
(
2
1
mv
2
)
Using unitary method,
4
3
(
2
1
mv
2
)→3 cm penetration
⇒
4
1
(
2
1
mv
2
)→1 cm penetration
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