If a body loses half of its velocity
on penetrating 3 cm in a wooden
block , calculate how much will it
penetrate more before coming to
rest.
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Answered by
30
Explanation:
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Answered by
51
Explanation:
Let the original velocity be 'u'. Using equations of motion,
=> v² = u² + 2aS, for situation when body loses 1/2 velocity, new velocity = u - u/2 = u/2.
=> (u/2)² = u² + 2a(3cm)
=> u²/4 - u² = 2a(0.03 m)
=> - 3u²/4 = 0.06 a
=> - 12.5u² = a
Hence, when body comes to rest,
=> 0 = (u/2)² + 2(12.5u²) S
=> u²/4 = 25u²S
=> 1/100m = S
=> 1/100 *100 cm= S
=> 1 cm = S
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