Question

if a body moves with velocity 10m/s after applying a force of 10N it's velocity becomes 20m/s by acceleration of 15m/s. What is the work done by the body?​

Answer 1

Answer:

Work done = 22.5 J

Explanation:

Work done = change in kinetic energy

V= 10m/sec

M =?

Second v. =20m/sec

F= 10N

(I) K. E =

$\frac{1}{2} \times m \times {v}^{2}$

$\frac{1}{2} \times f \times a \times {v}^{2}$

$\frac{1}{2} \times 10 \times 15 \times 100$

=7500J

On apliying same formula we get (2) K. E

=30000J

THEN WORK DONE = change in kinetic. E.

=( 30000-7500)J

=22500

=22.5J ANS.