Question

If a body moving with internal velocity of 2 MS power -1 has displacement of 48 in 6 seconds then the final velocity attended by body is

Answer 1

Appropriate Question :

If a body is moving with the initial velocity of 2 m/s has displacement of 48 m in 6 seconds then the final velocity attended by body is _____.

Answer:

14 m/s

Explanation:

In the given question, we've been provided that the velocity of the body is 2 m/s initially and it covers the displacement of 48 m in 6 seconds. We've been asked to calculate the velocity of the body finally. Basically, we can apply the 1st equation of motion that is ║ v = u + at ║to find the final velocity of the body but firstly we'll have to calculate acceleration which can be calculated by using 2nd equation of motion, that is ║ S = ut + ½at² ║.

Considering the given statements we have,

• Initial velocity, u = 2 m/s
• Displacement, s = 48 m
• Time taken, t = 6 s

We'll have to calculate acceleration first in order to calculate the final velocity. Acceleration is nothing but the rate of change in velocity. Its SI unit is m/s² and it is a vector quantity.

By using the second equation of motion,

$\twoheadrightarrow\quad\underline{\boxed{ \pmb{\mathfrak{s = }} \pmb{\mathfrak{ut + }} \dfrac{\pmb{\mathfrak{1}}}{\pmb{\mathfrak{2}}} \pmb{\mathfrak{a}}\pmb{\mathfrak{t}}^{\pmb{\mathfrak{2}}} }}$

Here, s denotes distance/displacement ; u denotes initial velocity ; t denotes time ; a denotes acceleration.

$\twoheadrightarrow\quad\sf { 48 = 2(6) + \dfrac{1}{2}a(6)^2}$

$\twoheadrightarrow\quad\sf { 48 = 12 + \dfrac{1}{2}a(36)}$

$\twoheadrightarrow\quad\sf { 48 = 12 + 18a}$

$\twoheadrightarrow\quad\sf { 48 - 12 = 18a}$

$\twoheadrightarrow\quad\sf { 36 = 18a}$

$\twoheadrightarrow\quad\sf { \cancel{\dfrac{36}{18}} = a}$

$\twoheadrightarrow\quad\boxed{ \textsf{\textbf{2}}\;\textsf{\textbf{ms}}^{\textsf{\textbf{-2}}} = \textsf{\textbf{a}} }$

Now, by using the first equation of motion,

$\twoheadrightarrow\quad\underline{\boxed{ \pmb{\mathfrak{v = u + at }}}}$

Here, v denotes final velocity ; u denotes initial velocity ; a denotes acceleration ; t denotes time.

$\twoheadrightarrow\quad\sf { v = 2 + 2(6)}$

$\twoheadrightarrow\quad\sf { v = 2 + 12}$

$\twoheadrightarrow\quad\underline{\boxed{ \textsf{\textbf{v}} = \textsf{\textbf{14}}\;\textsf{\textbf{ms}}^{\textsf{\textbf{-1}}} }}$

Therefore, final velocity of the body is 14 m/s.

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Answer 2

CONCEPT :-

these question is based on Motion in a Straight Line We have given that If a body moving with internal velocity of 2 MS power -1 displacement of 48 in 6 seconds first we have to write formula

S = ut + 1/2 at² we will calculate it we get

2 m /s then we have formula v = u + at we calculate it we get the answer 14 m/s

can displacement of a moving object be zero

Yes, displacement can be zero. displacement is the shortest distance between initial position and final position. But, as the initial and final position are same and distance between your home and home is zero, hence displacement is zero.

Distance v/s displacement

We know that the velocity of body is given by the slope of displacement time graph. So it is clear that initially slope of the graph is positive and after some time it becomes zero (corresponding to the peak of graph) and then it will become negative.

Average Acceleration

The average acceleration is defined as the ratio of change in velocity over the time interval = ∆V/∆t it is a vector quantity

QUESTION :-

If a body moving with internal velocity of 2 MS power -1 has displacement of 48 in 6 seconds then the final velocity attended by body is

GIVEN :-

If a body moving with internal velocity of 2 MS power -1 has displacement of 48 in 6 seconds

TO FIND :-

final velocity attended by body = ?

SOLUTION :-

u = 2 m/s , S = 48 m , t = 6s

S = ut + 1/2 at²

48 = 2 × 6 + 1/2 ( a × 36)

a = 36/18 = 2m/s²

Therefore,

v = u + at

v = 2 + (2 × 6)

v = 14m/s

Therefore velocity attained is 14m/s.