If a body of 25 kgs at rest acquires a velocity of
30m/s in 3 s due to application of a force, find the value of force
Answers
Answered by
1
HI there !!
Mass = m = 25 kg
Initial velocity = u = 0 m/s
Final Velocity = v = 30 m/s
Time = t = 3 sec
Law of motion :-
v = u + at
30 = 0 + 3a
a = 30/3
a = 10 m/s²
Force = F = ma
= 25 × 10 = 250 N
Mass = m = 25 kg
Initial velocity = u = 0 m/s
Final Velocity = v = 30 m/s
Time = t = 3 sec
Law of motion :-
v = u + at
30 = 0 + 3a
a = 30/3
a = 10 m/s²
Force = F = ma
= 25 × 10 = 250 N
pipi:
sorry didi
Answered by
2
hai friend,
here is your answer,
Formulas :-
Force =mass*acceleration
Acceleration =
final velocity -initial velocity /Time taken
Key points :-
At rest velocity =0m/s
Solution :-
a=30-0/3 m/s²
a=30/3=10m/s²
a=10m/s²
F=m*a
=25*10 kgm/s²
=250N
hope helped :)
here is your answer,
Formulas :-
Force =mass*acceleration
Acceleration =
final velocity -initial velocity /Time taken
Key points :-
At rest velocity =0m/s
Solution :-
a=30-0/3 m/s²
a=30/3=10m/s²
a=10m/s²
F=m*a
=25*10 kgm/s²
=250N
hope helped :)
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