If a body of mass 10 kg is acted upon by two forces of 8N and 12N making an angle of 60° with each other.Find the acceleration of the body
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Answer:
A body of mass 10 kg is acted upon by two perpendicular forces, 6N and 8N. The resultant acceleration of the body is
A
1ms
−2
at an angle of tan
−1
(
4
3
)w.r.t. 8N force.
B
0.2ms
−2
at an angle of tan
−1
(
4
3
)w.r.t. 8N force.
C
1ms
−2
at an angle of tan
−1
(
3
4
)w.r.t. 8N force.
D
0.2ms
−2
at an angle of tan
−1
(
3
4
)w.r.t. 8N force.
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ANSWER
Here, m=10 kg
The resultant force acting on the body is
F=
(98N)
2
+(6N)
2
=10N
Let the resultant force F makes an angle θ w.r.t. 8N force.
From figure, tanθ=
8N
6N
=
4
3
The resultant acceleration of the body is
a=
m
F
=
10kg
10N
=1ms
−2
The resulatnt acceleration is along the direction of the resulatnt force.
Hence, the resultant acceleration of the body is 1 ms
−2
at an angle of tan
−1
(
4
3
) w.r.t. 8N force.
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