Question

If a body of mass 3 kg is dropped from top of a
tower of height 250 m, then its kinetic energy
after 3 sec. will be
(a) 1126 J
(b) 1048 J
(c) 735 J
(d) 1296.5 J​

Answer 1

Answer:

Given:

1. mass of the body = 3kg

2. height of tower = 250m

3. Time = 3seconds

Now, velocity (v) = 250/3 m/s

= 83.3m/s

Kinetic energy = 1/2 mv²

= 1/2 × 3 × (83.3)²

= 10408.335j