Question

If a body of mass 40 kg is kept at a distance of 0.5 m from a body of
mass 60 kg, what is the mutual force of attraction between them?
a​

Answer 1

Answer:

Explanation: apply the formula of newtons law of gravitational force

F = GMm by r^2

so f =6.022 X 10^23 X 40 X60 BY 0.25

F = 6.022 X 10^23 X 600

  = 3613.2 X 10^23

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Answer 2

Answer:

F= 4*10^-8 newton

Explanation:

F= G m1* m2 / r^2

F= (6.67*10^-11)(40)(60) / (0.5)^2

F= 1.6*10^-7 / 0.25

F= 4*10^-8 newton.