Question

if a body of mass5kg raised vertically through a height of 1m then the work done is

Answer 1

The work done will be in the form of potential energy. As the displacement is in the direction opposite to the force acting i.e gravitational force, the work done will be negative.

W = -mgh

W = -5*9.8*1

W = -49 Joules

Answer 2

$\huge\mathfrak\red{ANSWER}$

-49J

Explanation:

IMPORTANT KEYWORDS :

WORK IS SAID TO BE DONE WHEN A FORCE IS APPLIED ON BODY AND THE BODY UNDERGOES DISPLACEMENT.

WORK IS ALSO THE PRODUCT OF THE FORCE AND DISPLACEMENT.

S. I UNIT OF WORK IS JOULE.

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WORK = FORCE × DISPLACEMENT.

IN THIS CASE —————>>>

FORCE = ?

DISPLACEMENT = 1m.

MASS = 5Kg.

NOW, FORCE = MASS × ACCELERATION.

ACCELERATION WHICH IS ACTING ON A GENERAL BODY IS = ACCELERATION DUE TO GRAVITY = g = 9.8m/s^2

THEREFORE IF WE CALCULATE FORCE APPLIED ON THIS BODY ---->>

FORCE = 5 × -9.8

$= 49n$

NOW WORK DONE ON BODY = 49 × 1

= -49 JOULE.

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BY SCIVIBHANSHU

THANK YOU

STAY CURIOUS.