Physics, asked by Darshana004, 11 days ago

If a body projected vertically upward with velocity 'u' and another body dropped from height 'h' in the same line at the same time, Show that

(a) they will meet after time t =h/ u

(b) Distance from top where they meet is x = (gt ^ 2)/2

plzzzz solve this its urgent ......​

Answers

Answered by jhansimerlla
0

Answer:

v=

 \sqrt{2 \\  \\ gh + u {}^{2} }  \\

Explanation:

v=

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