Question

if a body start with a certain velocity and after displacement of 40 m it looses 20%of it's velocity.Then calculate further displacement of body before it comes to rest
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Answer 1

Answer:

The distance traveled by the particle in the last 2 seconds = distance traveled by particle in nth second- distance traveled by particle in (n-2)th second

So,

s=21an2−21a(n−2)2

s=21a[n2−n2+4n−4]

s=2a[4n−4]

s=(2n−2)a=2a(n−1)(1)

Now,

Velocity, v=acceleration×time

v=a×n

(2)

Substitute value of 'a' from (2) to (1) we get,

s=n2v(n−1)

Explanation:

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