If a body starts from rest and has an acceleration 20cm/s. What is the distance covered by the body in first 8 s
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initial velocity =0
a=20cm/s
t=8sec
by the second equation of motion
s=ut+1/2at^2
s=0*8+1/2*20*8*8
s=0+640
s=640cm
a=20cm/s
t=8sec
by the second equation of motion
s=ut+1/2at^2
s=0*8+1/2*20*8*8
s=0+640
s=640cm
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