Question

If a body starts from rest and moves with uniform acceleration then distance covered by the body in t sec is proportional to t^2 . State the ratio of distance covered in 1 sec,2 sec and 3 sec

Answer 1

Answer:

The initial velocity is u=0ms−1

The acceleration is a=10ms−2

The time is t=5s

Apply the equation of motion

v=u+at

The velocity is

v=0+10⋅5=50ms−1

The distance travelled in the first 5s is

s=ut+12at2

=0⋅5+12⋅10⋅52=125m

The distance travelled in the following 10s is

s1=vt1=50⋅10=500m

The total distance travelled is

d=s+s1=125+500=625m