Question

If a body starts from rest and travels 120 cm in the 6th second, then what is the acceleration
(1) 0.20 ms-2
(2) 0.027 ms-2
(3) 0.218 ms-2
(4) 0.03 ms-2​

Answer 1

Answer:

C

Explanation:

Hi!

So according to the formula for nth second, we know that

sn= u+1/2a{2n-1}

n=the second in which we need to find the distance

On  putting the values we get

1.2 m= 0+1/2a{12-1} ( The body is at rest)

1.2m= 1/2A{`11}

2.4/11 =A

A=0.218 ms^-2

Thank you

I hope it helps