if a body starts from rest and travels 120 cm in the 6th second, then what is the acceleration.
a. 0.20 m/s
b. 0.027 m/s
c. 0.218 m/s
d. 0.03 m/s
plz tell me the method also .
Answers
Answered by
18
s=ut+1/2a(2n-1)
=1/2×a(2n-1)
1.2=1/2×a(2×6-1)
2.4/11=a
a=0.218m/s^2
Answered by
3
s=ut+1/2a(2n-1)
=1/2×a(2n-1)
1.2=1/2×a(2×6-1)
2.4/11=a
a=0.218m/s^2
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