If a body starts to move on a surface with a velocity of 20 metre per second due to friction it comes to rest after covering a distance of 40 metre the coefficient of friction will be
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Answer:
0.5
Explanation:
Stopping distance is calculated by
- S = u²/(2μg)
Where
- S = Stopping distance
- u = Initial velocity
- μ = Coefficient of friction
- g = Acceleration due to gravity
From above,
μ = u²/(2Sg)
= (20 m/s)² / (2 × 40 m × 10 m/s²)
= 400 / 800
= 0.5
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