Math, asked by smayuri389, 9 months ago

if a body starts to move with initial velocity 10m/s acceleration 2 m/s , find distance covered in 5s, and velocity after 5 sec​

Answers

Answered by ryanrtf3
0

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Answered by CharmingPrince
2

Answer:

Given:

  • u = 10\ m/s
  • a = 2\ m/s^2
  • t = 5 \ s

To find:

  • s = ?
  • v = ?

Solution:

\boxed{v = u + at}

\therefore v = 10 \ m/s + 2 \ m /s^2 \times 5 \ s

v = 10 \ m/s + 10 \ m/s

\boxed{\implies{\boxed{v = 10\ m/s}}}

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\boxed{s = ut + \dfrac{1}{2}at^2}

\therefore s= 10 \times 5 + \dfrac{1}{2}\times 2 \times 5

s = 50 \ m + 5 \ m

\boxed{\implies{\boxed{s = 5 5\ m}}}

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