If a body travels 1/3 distance with a velocity 2 ms – 1 , next 1/3 distance with velocity 4 ms – 1 and the remaining 1/3 distance with velocity 6 ms – 1 , then the mean velocity of the body in m/s is:
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Answer:
Let total distance d
Let time covered for first one third distance bet
1
Then t
1
=
4
d/3
=
12
d
t
2
be time for next two journeys
d−
3
d
=
3
2d
=2t
2
+6t
2
=8t
2
t
2
=
12
d
Averagevelocity=
Totaltime
Totaldistane
=
t
1
+2t
2
d
=
12
d
+
12
2d
d
=4m/s
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