Question

If a body travels with the speed of 5 m/s Afeer 2 seconds
its speed increased to 10 m/s.find acceleration. ​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Acceleration=2.5\:m/s^{2}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Initial \: speed(u) = 5 \: m/s \\ \\ \tt: \implies Time(t) = 2 \: sec \\ \\ \tt: \implies Final \: velocity(v) = 10 \: m/s \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Acceleration = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies 10 = 5 + a \times 2 \\ \\ \tt: \implies 10 - 5 = a \times 2 \\ \\ \tt: \implies 5 = 2 \times a \\ \\ \tt: \implies a = \frac{5}{2} \\ \\ \green{\tt: \implies a = 2.5 \: {m/s}^{2} } \\ \\ \green{\tt \therefore Acceleration \: of \: particle \: is \: 2.5 { \: m/s}^{2} } \\ \\ \blue{\bold{Some \: relate \: formula}} \\ \orange{\tt \circ \: {v}^{2} = {u}^{2} + 2as} \\ \\ \orange{\tt \circ \: s= ut+ \frac{1}{2} a {t}^{2} } \\ \\ \orange{\tt \circ \: Distance = Speed \times Time }$

Answer 2

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$\tt{\huge{\purple{ ............. }}}$

QUESTION :

If a body travels with the speed of 5 m/s Afeer 2 seconds

If a body travels with the speed of 5 m/s Afeer 2 secondsits speed increased to 10 m/s.find acceleration. .

SOLUTION :

From the above Question, we can gather the following information...

U = 5 m / s

V = 10 m / s

T = 5 Seconds.

According To Newton's first law of motion ,

A = ∆V / T

=> A = { V - U } / T

=> A = { 10 - 5 } / 2 m / s ^ 2

=> A = 2.5 m / s ^ 2

So the acceleration of the body is 2.5 m / s ^ 2.

ANSWER :

The acceleration of the body is 2.5 m / s ^ 2.