If a body travels with uniform acceleration 5 m.s^ 2 for 5 sec and with uniform acceleration 10 m.s^ 2 for next 10 sec then its average acceleration in m.s^ 2 is (A) 25/3 (B) 25 (C) 15/2 (D) 20/3
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Answers
Explanation:
If a body travels with uniform acceleration 5 m.s^ 2 for 5 sec and with uniform acceleration 10 m.s^ 2 for next 10 sec then its average acceleration in m.s^ 2 is (A) 25/3 (B) 25 (C) 15/2 (D) 20/3
ANSWER:
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V = u + at
After 5s
25 = u + 5a ——(1)
After 8s
34 = u + 8a ——(2)
Subtract equation (1) from equation (2)
34 - 25 = u + 8a - u - 5a
9 = 3a
a = 3 m/s^2
Substitute a = 3m/s^2 in equation (1)
25 = u + 5*3
u = 10 m/s
Distance travelled in 12th second
S = u + a(n - 1/2)
S = 10 + 3*(12 - 1/2)
S = 44.5m
Distance travelled in 12th second is 44.5m
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Explanation:
If a body travels with uniform acceleration 5 m.s^ 2 for 5 sec and with uniform acceleration 10 m.s^ 2 for next 10 sec then its average acceleration in m.s^ 2 is (A) 25/3 (B) 25 (C) 15/2 (D) 20/3
ANSWER:
Open in answr app
V = u + at
After 5s
25 = u + 5a ——(1)
After 8s
34 = u + 8a ——(2)
Subtract equation (1) from equation (2)
34 - 25 = u + 8a - u - 5a
9 = 3a
a = 3 m/s^2
Substitute a = 3m/s^2 in equation (1)
25 = u + 5*3
u = 10 m/s
Distance travelled in 12th second
S = u + a(n - 1/2)
S = 10 + 3*(12 - 1/2)
S = 44.5m
Distance travelled in 12th second is 44.5m