Question

If a bomb of mass 5 kg is projected with an initial
velocity of 60 m/s at an angle of 60° with respect
to the horizontal, and it explodes at the highest
point of its motion, then how far does the centre
of mass of the bomb fall from the point of
projection?
M1) 180/3 m
(2) 180 m
(3) 150 m
(4) 150/3 m​

Answer 1

Answer: 180√3m.

Explanation:

Answer 2

Answer:  

The distance the bomb's Centre of mass falls from the point of projection is 180/3 m if a bomb with a mass of 5 kg is projected at an initial velocity of 60 m/s and an angle of 60° with respect to the horizontal.

Explanation:

What is meant by initial velocity?

• The velocity at time interval t = 0 is known as the initial velocity and is denoted by the symbol u.

• It is the speed at which a motion begins. You might find the problems based on initial velocity below to be useful. When gravitational force is first exerted on an object, its initial velocity describes how quickly it moves.

• The final velocity, on the other hand, is a vector quantity that gauges the speed and direction of a moving object after it has experienced its maximum acceleration.

• When a car begins moving, its initial velocity is zero. A projectile will have a greater initial velocity if it is thrown into the area.

To learn more about initial velocity, refer to:

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