Question

if a bowler throws the ball at 143 km/h and the boundary is at 63 m. then how much force required by batsman to hit a six​?

Answer 1

the force needed is 24 86N.

the force can be calculated using simple equations of paarabola .the ball will have the same speed plus the force of the batsman after the batsman hits it

let force =F

here,

speed of ball, V=143km/h=39.72m/s

speed of ball after the batsman hits it =(V+F)km/h

length of blundary,R=63m

angle of shot=a=45°

gravitational force=9.81m/s

R=v2sin (2a)/g

or,R=(V+F)2=Rg/sin (2a )

hence F=24.86

the force needed is 24.86 newton