If a box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains no defective bulbs.
A) 5/12 B) 7/12 C) 3/14 D) 1/12
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HEY! HERE YOUR ANSWER
A) 5/12
B) 7/12
C) 3/14
D) 1/12
Answer: A) 5/12
Explanation:
Total number of elementary events = 10C5
Number of ways of selecting exactly one defective bulb out of 3 and 4 non-defective out of 7 is 3C1*7C4
So,required probability =3C1*7C4/10C5 = 5/12.
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