Math, asked by amulya1975, 6 months ago

if a box contains 16 red balls 12 blue balls and 22 green balls what's is the probability drawing a ball which is in a red b either red or blue c not green​

Answers

Answered by singhkulwinder6746
2

Answer:

total no of balls= 12+22+16=50

probability of red balls= 16/50 simplest8/25

probability of green balls= 22/50 simplest 11/25

probability of blue balls = 12/50 simplest 6/25

Step-by-step explanation:

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Answered by shreydale411
3

Answer:

total no. of balls(red+blue+green,ignoring their colors)- 50

a) no.of red balls-16

probablity of getting a red ball-no.of red balls/total balls

hence,16/50 is the required ansr(you can simplify it further as well).

b)either red or blue(probablity of getting a ball which isnt green in color)

total no. of balls (red plusblue) - 28

probablity of getting either red or blue ball- 28/50

c)total no. of non green balls is (red+blue=28)

hence,28/50 is tHe required ansr.

hope it helps.

Step-by-step explanation:

note-the denominator is always the sum of the balls irrespective of their colors whereas the numerator varies

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