Question

If a box contains 4 red balls, 5 green balls and 6 blue balls find the probility a) getting a green ball b) getting a blue ball c) Non red ball

Answer 1

Here is Your Answer :-

Solution:- (a) getting a green ball

Total balls (S)=15
Total Green Balls (E)=5
P(n)=P(E)/P(S)
P(n)=5/15 —>1/3

So the Probability of getting a Green ball is 1/3.

(b)getting a blue ball

Total balls (S)=15
Total Blue Balls (E)=6
P(n)=P(E)/P(S)
P(n)=6/15

So the Probability of getting a Blue ball is 6/15.

(c)Non red ball

—>Non red balls are Green balls and Blue balls so the total number of Green and Blue balls are 11.

Total balls (S)=15
Total Green and Blue balls (E)=11
P(n)=P(E)/P(S)
P(n)=11/15

So the Probability of getting a Non red ball is 11/15.

Hope it Helps You...

Answer 2

Answer:

(a)=1/3 , (b)=2/5 , (c)=11/15

Step-by-step explanation:

I hope it will help you