Question

If a box contains 6 red ball and 4 blue balls, the probability of drawing first the red ball and then the blue ball is

Answer 1

Answer:

Total no. of balls = 10

P(getting the red ball) = 6/10= 3/5

Now since one ball is removed .

no. of balls in box = 9

P(getting blue ball) = 4/9

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Answer 2

Answer:

given

n (s)=10

p (getting a red ball) =n (e)/n (s)=6/10=3/5

and p(getting a blue ball)=n (e)/n (s)=4/10=2/5