If a box is pushed across the floor with a force of 130N the frictional force between the box and the floor is 30 N over a time period of 5 sec . Determine the following : (a) What is the net force acting on it ? (b) Acceleration acting upon the box if its starts from reat and attains certain KE after being pushed 25m . (c) Also, find mass of the box.(d) What will be the KE and final velocity?
Answers
Net force = 100 N
Acceleration acting upon the box = 2 ms⁻²
Mass of the box = 65 Kg
Kinetic energy = 3250 J
Final velocity = 10 m/s
Explanation:
=> It is given that,
Force applied on box, F = 130 N
Friction force between the box and the floor, Ff = 30 N
Time period, t = 5 sec
(a) Net force:
Fnet = F - Ff
= 130 - 30
= 100 N
(b) ) Acceleration acting upon the box, f:
if its starts from rest and attains certain KE after being pushed 25m then,
Initial velocity, u = 0
Displacement, s = 25 m
thus, displacement, s = ut + 1/2 ft²
∴ 25 = 0* 5 + 1/2 * f * (5)²
25 = 0 + 1/2 * f * 25
f = 2 ms⁻²
(c) Mass of the box, M :
Mass = Force / acceleration
=130/2
= 65 kg
(d) Kinetic energy and final velocity :
=> final velocity, v:
v² = u² + 2fs
v² = (0)² + 2 * 2 * 25
v² = 100
v = 10 ms⁻¹
=> kinetic energy, KE:
KE = 1/2 mv²
= 1/2 * 65 * (10)²
= 1/2 * 65 * 100
= 3250 J
Learn more:
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Q: 2 A block of mass 10 kg placed on rough horizontal surface having coefficient of friction 0.5,if a horizontal force of 100 N is acting on it then acceleration of the block will be(g=10 m/s2).
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11th
Physics
Laws of Motion
Problems on Friction
The sliding frictional forc...
PHYSICS
The sliding frictional force between 4 kg box and the floor is 15 N. It is pushed across the floor with a constant force such that it accelerates at 0.8ms
−2
. What is the force applied to the box?
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ANSWER
Mass of the block =m= 4kg
Acceleration a=0.8m/s
2
Therefore, net force acting on the block *in the direction of motion =F=ma=3.2N
This force is achieved after overcoming the opposing frictional force of 15N(f)
Therefore, the total force to be applied
F' =F+f=15+3.2= 18.2 N
hence the force applied to the box is 18.2N.
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