Question

If a box of 12 bulbs, 3 are defective. If 4 are selected, find the probability of getting

a. No defective bulb
b. 1 defective bulb
c. 3 defective bulb

Answer 1

Answer:

a. 9/4

b. 1/4

c. 3/4plesae mark me branliest

Answer 2

Step-by-step explanation:

Defective bulb= 12-3=9

defective bulb= 3

1. 9/12 = 3/4
2. 1+3/12 = 4/12
3. 3+1/12 = 4/12