Question

If a box with a mass of 6 kilograms is pushed with a net force of 10 to the right.

What would be the acceleration of the box


A.) .6 meters per second squared
B.)0.0 meters per second squared
C.) 1.67 meters per second squared
D.) 60 meters per second squared

Answer 1

Answer:

The Uniting friction =μ

s

R

μ

s

mg=0.5×60×10=300N

Kinetic friction =μ

k

R=μ

k

mg

=0.4×60×10=240N

Force applied = 300 N

Net accelerating force

= Applied force - kinetic friction

⇒ ma = 300 - 240 = 60

⇒a=

60

60

=1m/s

2