Question

If a boy can throw a stone to a maximum height of 25 , he can throw the same stone to a distance of?

Answer 1

Answer:

For Vertically projected up body maximum height (H) is given as

H = u^2 / (2g) ……[1]

For the same body with same initial initial velocity the horizontal distance travelled when thrown at an angle (θ) is given as

R = u^2 Sin(2θ) / g

Maximum horizontal distance is given as

R = u^2 / g ……[2]

Compare equations 1 and 2

R = 2 H

R = 2 × 10

R = 20 m