Question

If a boy can throw a stone to a maximum height of 25m he can throw the same stone to a distance of?

Answer 1

Answer:

50m.hope the answer helped you.... Good day

Explanation:

S=25m

a=-10

V=0

0=u^2-2*10*25

0=u^2-500

U^2=500

U=10 root5

Range is max when the boy throws the stone at an angle of 45 degree

Rmax=u^2/g

=500/10

=50m

Answer 2

Answer: He can throw the same stone to a maximum distance of 50m

Explanation:

Equation for max height of projectile

H = V^2 / 2g

V^2 = 2gH ...............eq1

Equation for maximum range:

R = V^2 / g...............eq2

Putting the value of V^2 from eq1 in eq2:

R = 2gH / g

Hence

R = 2H = 2 × 25 = 50 m