If a boy rides his bicycle 10 km at an average speed of 12 km/hr and again travels 12 km at an average speed of 10 km/hr, find his average speed for the entire trip?
Answers
Answered by
7
time taken to cover 10 km = 10/12 hr = 5/6hr
time taken to cover 12 km = 12/10 hr = 6/5 hr
total distance travelled = 10+12km = 22km
total time taken = 6/5+5/6 hr
=61/30 hr
average speed = 22km / 61/30hr
=660/61km/hr
time taken to cover 12 km = 12/10 hr = 6/5 hr
total distance travelled = 10+12km = 22km
total time taken = 6/5+5/6 hr
=61/30 hr
average speed = 22km / 61/30hr
=660/61km/hr
Answered by
6
Total distance travelled = (10+12) km =22 km
Total time taken = (10/12) + (12/10) = (100+144)/120 = 244/120 hr = 61/30 hour
Avearge speed = (Total distance)/(Total time)
= (22)/(61/30)
= (22 ×30)/61
= (660/61) km/hr
= 10.81 km/hr
Hope it helps
Total time taken = (10/12) + (12/10) = (100+144)/120 = 244/120 hr = 61/30 hour
Avearge speed = (Total distance)/(Total time)
= (22)/(61/30)
= (22 ×30)/61
= (660/61) km/hr
= 10.81 km/hr
Hope it helps
misa3:
you have also answered the same question
Hmmm, Can't i ?? ;)
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