Question

If a boy see the top of the tower from a point 60m from its foot with an angle of 30 degrees find the height of tower...
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Answer 1

Height of tower be h

Distance of boy from the tower = 60 m

angle, θ = 30°

Let the height of tower be the perpendicular and distance of boy from the tower be base of a right angled triangle.

So,

==> tan θ = Perpendicular / Base

==> tan 30° = h / 60

==> 1/√3 = h/60

==> h = 60/√3 m

==> h = 60√3 / 3

==> h = 20√3

Hence , height of the tower is 20√3 m

Answer 2

☛ Question :-

If a boy see the top of the tower from a point 60m from its foot with an angle of 30 degrees find the height of tower.

☛ To find :-

• Height of the tower.

☛ Solution :-

• Let us consider ∆ABC, ∠B = 90°.

• Let AB be the tower.

• ∠ACB is the angle of elevation i.e., 30° and the foot of the tower is 60m away from the point C.

➞ tan 30° = Perpendicular / Base

➞ 1/√3 = AB/60

➞ 60/√3 × √3/√3 = AB

➞ 60√3/√3 = AB

➞ AB = 20√3

∴ Height of the tower = 20√3 m