If a boy walks from his house to school at 4km/hr, he reaches vthe school 10 minutes earlier than the scheduled time. however if he walks at the rate of 3km/hr, he reaches 10 minutes late. the distance of school from his house is
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Step-by-step explanation:
speed = distance / time
distance = speed×time
let the distance = d and schedule time be x
time = 10min = 10/60 = 1/6
according to question :
4×(x - 1/6) = d
4x - 4/6 = d --(i)
3×(x + 1/6) = d
3x + 3/6 = d --(ii)
by equation (i) and (ii)
4x - 4/6 = 3x + 3/6
4x - 3x = 4/6 + 3/6
x = 7/6 hrs
put the value in equation (i)
4×(7/6 - 1/6) = d
d = 4 km
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