Math, asked by GautamPrabhu2639, 1 year ago

If a broker charges 2 % brokerage from the buyer and the seller both, find the following on a deal of Rs.70,000 struck with the help of the broker :
(1) How many rupees should the buyer pay?
(2) How many rupees would the seller get?
(3) What is the total brokerage got by the broker?

Answers

Answered by hukam0685
0

Dear Student,

Answer: Buyer pay = 71,400 Rs

Seller get = 68,600 Rs

Broker received = 2800 Rs

Solution:

Deal amount = 70,000 Rs

Broker's Commission = 2 % from buyer and 2 % from seller

let us first calculate 2% of 70,000 Rs

= (2 x 70,000)/100

=1400 /- Rs

1) Buyer pay amount to = Seller + broker

= 70,000 + 1400

= 71,400 Rupees

2 ) Seller Receive amount from buyer and will give 2 % to the broker

Amount which seller receive = 70,000 - 1400

= 68,600 Rupees

3 ) Broker get fro both:

Amount which broker received = 1400+1400 = 2800 Rupees

Hope it helps you.

Thanks for asking such a great question.

Keep studying.

Answered by abhi178
0
broker charges 2% brokerage from the buyer and the seller both.

(1) Brokerage paid by the buyer = 2 % of 70,000
= 2 × 70,000/100
= 2 × 700
= 1,400 Rs.

(2) Brokerage paid by the seller = 2 % of 70,000
= 2 × 70,000/100
= 2 × 700
= 1,400 Rs.

(3) total brokerage got by the broker = brokerage got by the seller + brokerage got by the buyer
= 14,00 + 1,400 = 2,800 Rs.
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