If a bulb labbelled 100w/230V is connected to 150V power supply. What its power
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Answer:
Resistance of the bulb R=
P
V
2
where P=100W and V=200 V.
∴ R=
100
(200)
2
=400Ω
Actual power consumption P
′
=
R
V
1
2
where V
1
=160 V
∴ P
′
=
400
(160)
2
=64W
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