"If a bullet of mass 20g is moving with a speed of 150 m s-1 strikes a target and is brought to
rest after piercing 10 cm into it, then calculate the average force of resistance offered by the
target."
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Answered by
85
given:
mass=m=20g=20/1000=0.02kg
Initial velcoity=u=150m/s
Final velocity=0m/s
s=10cm=0.1m
According to Work _ Kinetic Energy Theorm
k-K1=W-Fs
1/2mu²-0=Fs
F=mu²/2s
=0.02x(150)²/2x0.1
=2250N
∴The average force of resistance offered by the target is 2250N
mass=m=20g=20/1000=0.02kg
Initial velcoity=u=150m/s
Final velocity=0m/s
s=10cm=0.1m
According to Work _ Kinetic Energy Theorm
k-K1=W-Fs
1/2mu²-0=Fs
F=mu²/2s
=0.02x(150)²/2x0.1
=2250N
∴The average force of resistance offered by the target is 2250N
Answered by
15
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