Question

If a bullet of mass 5 g moving with velocity 200m/s,penetrates the wooden block upto 6 cm.Then the average force imposed by the bullet on the block is-----
a)8300N
b)1667N
c)2628N
d)0​

Answer 1

Answer:

Given,

Mass of the bullet = 5g = 0.5kg

Initial Velocity = 200m/s

Final Velocity = 0

Distance = 6cm = 0.06m

By Applying v^2-u^2=2as

0^2-200^2=2×a×0.06

40000 = 2×a×0.06

40000 = 0.12a

a = 333,333m/s^2

We know that,

Force = mass×accleration

= 0.5×333,333

= 166666.5N.

Answer 2

Answer:

The answer is a option A