Question

If a bullet of mass 5 gram moving with velocity 100 meter per second penetrates the wooden block up to 6 cm. Then the average force imposed by the bullet on the block is

Answer 1

Here too we use equation of motion
v^2 = u^2 + 2as
2as = v^2 - u^2
2 x a x (6/100) = 0 - (100)^2
12a / 100 = - 10000
a = -1000000 / 12 m/s^2
This is the average retardation of the bullet
Avg force F = m a
= (5/1000) x 1000000 / 12 = 416.66 N
approx 417 newton
HOPE THIS IS USEFUL