If a bullet of mass m is fired from a gun of mass M with velocity u. The magnitude of Recoil velocity of the gun is V=__________.
Answers
Answer:
the answer for this question is v = [- m /M] x u
Explanation:
LET US ASSUME THAT THE MASS OF THE GUN BE M MASS OF THE BULLET BE m and THE VELOCITY OF THE BULLET AFTER FIRING BE u AND THE RECOIL VELOCITY OF THE GUN BE v AND THE INITIAL VELOCITY OF THE GUN AND THE BULLET BEFORE FIRING BE V
SO ACCORDING TO LAW OF CONSERVATION OF LINEAR MOMENTUM
MOMENTUM BEFORE FIRING = MOMENTUM AFTER FIRING
SO (M + m) V = mu + Mv
V = 0 SINCE THE BULLET AND GUN ARE IN REST BEFORE FIRING
SO (M+m) 0 = mu + Mv
SO Mv + mu = 0
SO Mv = -m x u
THEREFORE v = [-m/M] x u
the answer of v will be in negative indicating that the recoil velocity of the gun is in the opposite to that of the bullet
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