Math, asked by aryaprajapati820, 2 days ago

If a bullock-cart carries 3000 bricks and a camel-cart carries 2000 bricks, then how many total bricks are carried by two such bullock-carts and three such camel-carts ?​

Answers

Answered by kanishkchhaparwal140
3

Answer:

12000

Step-by-step explanation:

step 1 quantities

bullock cart -3000

camel cart -2000

step 2

how many times it carries

bullock cart -2

camel cart -3

so (3000×2) +(2000×3 )

=3000×2 =6000+2000×3= 6000

so 6000+6000 =12000

Answered by PoojaBurra
0

Given: A bullock-cart carries 3000 bricks and a camel-cart carries 2000 bricks.

To find: The total bricks are carried by two such bullock-carts and three such camel-carts.

Solution:

  • If one bullock-cart can carry 3000 brickes then, two such bullock-carts would be able to carry,

        2 * 3000 = 6000

  • If one camel-cart can carry 2000 brickes then, three such camel-carts would be able to carry,

        3 * 2000 = 6000

  • Two bullock-carts could carry 6000 bricks and three camel carts could carry 6000 bricks, and hence, they can totally carry,

        6000 + 6000 = 12000

Therefore, the total bricks are carried by two such bullock-carts and three such camel-carts is 12000.

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