If a bus decreases its speed from 100 km/h to 60 km/h in 5 s. find acceleration of the bus
Answers
Answer:
acceleration of the bus
= change in velocity/ time taken
now, 100 km/h = 100× 5/18 m/s = 250/9 m/s
60 km/h = 60×5/18 m/s = 150/9 m/s
or, acceleration
=(150/9 - 250/9) / 5
= -100/45 m/s^2
= -2.22 m^2
Answer:
Ans. 1.72 m/s
Explanation:
Initial speed , u = 100km/hr.
= 100×1000m/60×60s
= 1000/36
= 25.2m/s
( to convert 100Km into meter and hour in second)
final speed, v = 50km/h
= 50×1000m/60×60s
= 500/36
= 16.6m/s
Acceleration = ?
time = 5s
v = v + at
16.6 = 25.2 + a × 5
5a = 25.2 - 16.6
5a = 8.6
a = 8.6/5
a = 1.72m/s
Acceleration of the bus is 1.72m/s.
Hope this helps you