If a bus moves 60 kmph it will have 3 hours delay. if it moves 90 kmph it will arrive 1 hour earlier. how many kilometers is this route?
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let route distance =x km
and bus actual velocity .=y km/h
x/60=y+3 ----------------(1)
again ,
x/90=y-1. -----------------(2)
solve equations (1) and (2).
x/60 -x/90=4
x(90-60)/60 x 90=4
x=4 x 60 x 90/30=720km
hence ,
route =720 km
and bus actual velocity .=y km/h
x/60=y+3 ----------------(1)
again ,
x/90=y-1. -----------------(2)
solve equations (1) and (2).
x/60 -x/90=4
x(90-60)/60 x 90=4
x=4 x 60 x 90/30=720km
hence ,
route =720 km
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