Question

If
a bus travelling at 20 m/s is subjeated to a
steady deceleration of m/s², how long will it
take to come to rest?​

Answer 1

Answer:

5 seconds

Explanation:

★ Given :-

• Initial velocity (u) = 20m/s

• Acceleration (a) = 5m/s²

• Final Velocity (v) = 0m/s

★ To Find :-

• Time (t) = ?

★ Solution :-

We know 1st Kinematics Equation,

$✓ \: v = u + at$

Here,

• V = Final Velocity

• U = Initial Velocity

• A = Acceleration

• T = Time

Placing Values,

$⟶20 = 0 + 5 \times t$

$⟶20 = 0 + 5t$

$⟶20 = 5t$

$⟶t = \frac{\cancel{20}}{\cancel{5}}$

$⟶t = 4sec$

⛬ It will take 4 sec to come in rest.